Which of the following species would not be i | vedclass

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Forma

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All of the above are involved in the reaction.

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(D) The Hoffmann rearrangement involves the following steps:$1$. Formation of $N$-bromamide by the reaction of amide with $Br_2$ and $NaOH$.$2$. Formation of an acyl nitrene or direct rearrangement of the $N$-bromoamide anion to an isocyanate.$3$. The isocyanate is then hydrolyzed to the amine.Looking at the provided mechanism in the solution image,the species involved are:$(a)$ $N$-bromocyclohexanecarboxamide$(b)$ The conjugate base of the $N$-bromoamide$(c)$ Cyclohexyl isocyanateSince all these species are intermediates or products in the mechanism of the Hoffmann rearrangement,option $D$ is the correct answer.

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

Similar Questions

Product $(E)$ is

Primary and secondary amines can be distinguished by $:-$

The following transformation can be accomplished by:

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$
$C$. Bromobenzene + $AgCN$
$D$. Aniline + $CHCl_3$ + $Aq. NaOH$
$E$. $2-$Phenylethyl bromide + $KCN$

Benzyl isocyanide can be obtained by:
Choose the correct answer from the options given below:

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